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2. Suppose the charge on the sphere increases by
∆
q
in time
∆
t
. Then, in that time its
potential increases by
∆
∆
V
q
r
=
4
0
π
ε
,
where
r
is the radius of the sphere. This means
∆
∆
qr
V
=
4
0
π
. Now,
∆
q
= (
i
in
–
i
out
)
∆
t
,
where
i
in
is the current entering the sphere and
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Charge, Current

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