ch26-p016 - 16. (a) i = V/R = 23.0 V/15.0 103 = 1.53 103 A....

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16. (a) i = V / R = 23.0 V/15.0 × 10 –3 = 1.53 × 10 3 A. (b) The cross-sectional area is Ar D == ππ 2 1 4 2 . Thus, the magnitude of the current density vector is J i A i D = × × 4 4 153 10 541 10 2 3 3 2 72 π π . . A 6.00 10 m A/m .
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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