ch26-p034 - 34. We follow the procedure used in Sample...

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Substituting the values given, we obtain 4 2 3 (30.0 m)(7.80 10 A) 0.70 m 5.22 10 A 2 (4.00 10 ) (35.0 m)(35.0 m 0.70 m) i π Ω⋅ × == × ×Ω + . 34. We follow the procedure used in Sample Problem 26-5. Since the current spreads uniformly over the hemisphere, the current density at any given radius r from the striking point is 2 /2 JI r = . From Eq. 26-10, the magnitude of the electric field at a radial distance r is 2 2 w w I EJ r ρ , where 30 m w =Ω
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