ch26-p040 - 10 18 J. 40. (a) Referring to Fig. 26-32, the...

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(b) Eq. 24-6 immediately gives 12 eV, or (using e = 1.60 × 10 19 C) 1.9 × 10 18 J for the work done by the field (which equals, in magnitude, the potential energy change of the electron). (c) Since the electrons don’t (on average) gain kinetic energy as a result of this work done, it is generally dissipated as heat. The answer is as in part (b): 12 eV or 1.9
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Unformatted text preview: 10 18 J. 40. (a) Referring to Fig. 26-32, the electric field would point down (towards the bottom of the page) in the strip, which means the current density vector would point down, too (by Eq. 26-11). This implies (since electrons are negatively charged) that the conduction-electrons would be drifting upward in the strip....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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