52. (a) Using Table 26-1 and Eq. 26-10 (or Eq. 26-11), we have ()82622.00A||| |1.69 10m1.69 10 V/m.2.00 10 mEJρ−−−⎛⎞==×Ω⋅=×⎜⎟×⎝⎠GG(b) Using L= 4.0 m, the resistance is found from Eq. 26-16: R= L/A= 0.0338 Ω. The rate of thermal energy generation is found from Eq. 26-27:
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