ch26-p058 - 58. (a) The current is i= Vd 2 (1.20...

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(b) The magnitude of the current density vector is 62 22 2 44 ( 1 . 7 4 A ) | | 2.15 10 A/m . in.)(2.54 10 m/in.)] ii J Ad ππ == = = × [(0.0400 × G (c) E = V / L = 1.20 V/33.0 m = 3.63 × 10 –2 V/m. (d) P = Vi = (1.20 V)(1.74 A) = 2.09 W.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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