75. (a) In Eq. 26-17, we let ρ= 20where 0is the resistivity at T0= 20°C: ρρρ ρ ρα−=−000002TTbg, and solve for the temperature T: =+=°+×≈°−03120143 10250αCKC../(b) Since a change in Celsius is equivalent to a change on the Kelvin temperature scale,
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.