ch26-p075 - 75. (a) In Eq. 26-17, we let = 20 where 0 is...

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75. (a) In Eq. 26-17, we let ρ = 2 0 where 0 is the resistivity at T 0 = 20°C: ρρ ρ ρ ρα −= 00 0 0 0 2 TT bg , and solve for the temperature T : =+=°+ × ≈° 0 3 1 20 1 43 10 250 α C K C. ./ (b) Since a change in Celsius is equivalent to a change on the Kelvin temperature scale,
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