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Unformatted text preview: 3. The chemical energy of the battery is reduced by ∆E = qε, where q is the charge that
passes through in time ∆t = 6.0 min, and ε is the emf of the battery. If i is the current,
then q = i ∆t and
∆E = iε ∆t = (5.0 A)(6.0 V) (6.0 min) (60 s/min) = 1.1 × 104 J.
We note the conversion of time from minutes to seconds. ...
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