ch27-p008 - ) = 25 mA. Then the resistance of resistor 1...

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8. (a) The loop rule leads to a voltage-drop across resistor 3 equal to 5.0 V (since the total drop along the upper branch must be 12 V). The current there is consequently i = (5.0 V)/(200
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Unformatted text preview: ) = 25 mA. Then the resistance of resistor 1 must be (2.0 V)/ i = 80 . (b) Resistor 2 has the same voltage-drop as resistor 3; its resistance is 200 ....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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