across the battery is R ' = R 1 + R = 12 Ω . Thus, the current through R ' is (12V)/ R ' = 1.0 A, which is the current through R . By symmetry, we see one-third of that passes through any one of those 18 Ω resistors; therefore, i 1 = 0.333 A. (b) The direction of i 1 is clearly rightward. (c) We use Eq. 26-27: P = i 2 R ' =
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.