across the battery is
R
'
=
R
1
+
R
= 12
Ω
.
Thus, the current through
R
'
is (12V)/
R
'
= 1.0 A,
which is the current through
R
.
By symmetry, we see onethird of that passes through
any one of those 18
Ω
resistors; therefore,
i
1
= 0.333 A.
(b) The direction of
i
1
is clearly rightward.
(c) We use Eq. 2627:
P = i
2
R
'
=
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Current

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