ch27-p020 - 20. (a) Here we denote the battery emfs as V1...

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The terminal voltage of battery 1 is V 1 T and (see Fig. 27-4(a)) is easily seen to be equal to V 1 ir 1 ; similarly for battery 2. Thus, V 1 T = V 1 12 1 12 () rV V rrR + ++ , V 2 T = V 2 + + + . The problem tells us that V 1 and V 2 each equal 1.20 V. From the graph in Fig. 27-36(b) we see that V 2 T = 0 and V 1 T = 0.40 V for R = 0.10 . This supplies us (in view of the above relations for terminal voltages) with simultaneous equations, which, when solved,
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