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The terminal voltage of battery 1 is
V
1
T
and (see Fig. 274(a)) is easily seen to be equal to
V
1
−
ir
1
; similarly for battery 2.
Thus,
V
1
T
=
V
1
–
12 1
12
()
rV V
rrR
+
++
,
V
2
T
=
V
2
–
+
+
+
.
The problem tells us that
V
1
and
V
2
each equal 1.20 V.
From the graph in Fig. 2736(b)
we see that
V
2
T
= 0 and
V
1
T
= 0.40 V for
R
= 0.10
Ω
.
This supplies us (in view of the
above relations for terminal voltages) with simultaneous equations, which, when solved,
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 Spring '08
 Any
 Physics

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