The terminal voltage of battery 1 is V1Tand (see Fig. 27-4(a)) is easily seen to be equal to V1− ir1 ; similarly for battery 2. Thus, V1T= V1–12 112()rV VrrR+++, V2T= V2– +++. The problem tells us that V1and V2each equal 1.20 V. From the graph in Fig. 27-36(b) we see that V2T= 0 and V1T= 0.40 V for R= 0.10 Ω. This supplies us (in view of the above relations for terminal voltages) with simultaneous equations, which, when solved,
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