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Unformatted text preview: 22. (a) Let the emf of the solar cell be ε and the output voltage be V. Thus,
V = ε − ir = ε − FG V IJ r
H RK for both cases. Numerically, we get We solve for ε and r. 0.10 V = ε – (0.10 V/500 Ω)r
0.15 V = ε – (0.15 V/1000 Ω)r. (a) r = 1.0×103 Ω.
(b) ε = 0.30 V.
(c) The efficiency is
V2 /R
0.15V
=
= 2.3×10−3 = 0.23%.
−3
2
2
Preceived (1000Ω ) ( 5.0cm ) ( 2.0 ×10 W/cm ) ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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