27. Let
i
1
be the current in
R
1
and take it to be positive if it is to the right. Let
i
2
be the
current in
R
2
and take it to be positive if it is upward.
(a) When the loop rule is applied to the lower loop, the result is
21
1
0
iR
ε
−
=
.
The equation yields
i
R
1
2
1
50
0 050
==
=
.
.
V
100
A.
Ω
(b) When it is applied to the upper loop, the result is
123
2
2
0
−
−
−
=
.
The equation gives
2
2
6.0 V 5.0 V
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Current

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