27. Let i1be the current in R1and take it to be positive if it is to the right. Let i2be the current in R2and take it to be positive if it is upward. (a) When the loop rule is applied to the lower loop, the result is 2110iRε−=. The equation yields iR121500 050===..V100A.Ω(b) When it is applied to the upper loop, the result is 123220−−−=. The equation gives 226.0 V 5.0 V
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.