ch27-p029 - 29. Let r be the resistance of each of the...

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29. Let r be the resistance of each of the narrow wires. Since they are in parallel the resistance R of the composite is given by 19 Rr = , or R = r /9. Now rd = 4 2 ρ A / π and RD = 4 2 A / π , where is the resistivity of copper. A = π d 2 /4 was used for the cross-sectional area of a single wire, and a similar expression
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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