Unformatted text preview: Thus, by the loop rule (since the battery voltage has not changed) the voltage across R 1 has decreased a corresponding amount. When the switch was open, the voltage across R 1 was 6.0 V (easily seen from symmetry considerations). With the switch closed, R 1 and R 2 are equivalent (by Eq. 2724) to 3.0 Ω , which means the total load on the battery is 9.0 Ω . The current therefore is 1.33 A which implies the voltagedrop across R 3 is 8.0 V. The loop rule then tells us that voltagedrop across R 1 is 12 V – 8.0 V = 4.0 V. This is a decrease of 2.0 volts from the value it had when the switch was open....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Current

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