37. (a) We note that the R1resistors occur in series pairs, contributing net resistance 2R1in each branch where they appear. Since ε2= 3and R2= 2R1, from symmetry we know that the currents through 2and 3are the same: i2= i3= i. Therefore, the current through 1is i1= 2i. Then from Vb– Va= 2– iR2= 1+ (2R1)(2i) we get ()21124.0V2.0V0.33A.441.02.0iRR−−===+Ω+ΩTherefore, the current through
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.