(f) The direction is leftward. See the results in part (a). (g) The voltage across R1equals VA: (0.0382 A)(100 Ω) = +3.82 V. 38. (a) Using the junction rule (i1= i2+ i3) we write two loop rule equations: ε122 231233 23100−−+=+=iRi i Rbgbg.Solving, we find i2= 0.0109 A (rightward, as was assumed in writing the equations as we did), i3= 0.0273 A (leftward), and
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