ch27-p038 - 38. (a) Using the junction rule (i1 = i2 + i3)...

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(f) The direction is leftward. See the results in part (a). (g) The voltage across R 1 equals V A : (0.0382 A)(100 ) = +3.82 V. 38. (a) Using the junction rule ( i 1 = i 2 + i 3 ) we write two loop rule equations: ε 12 2 231 23 3 231 0 0 −− + = + = iR i i R b g bg . Solving, we find i 2 = 0.0109 A (rightward, as was assumed in writing the equations as we did), i 3 = 0.0273 A (leftward), and
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