ch27-p040 - 40. (a) Resistors R2, R3 and R4 are in...

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40. (a) Resistors R 2 , R 3 and R 4 are in parallel. By finding a common denominator and simplifying, the equation 1/ R = 1/ R 2 + 1/ R 3 + 1/ R 4 gives an equivalent resistance of 234 23 24 34 (50.0 )(50.0 )(75.0 ) (50.0 )(50.0 ) (50.0 )(75.0 ) (50.0 )(75.0 ) 18.8 . RRR R RR RR RR ΩΩ == ++ +Ω =Ω Thus, considering the series contribution of resistor R 1 , the equivalent resistance for the network is R eq = R 1 + R = 100 + 18.8 = 118.8 Ω ≈ 119 . (b)
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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