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40. (a) Resistors
R
2
,
R
3
and
R
4
are in parallel. By finding a common denominator and
simplifying, the equation 1/
R
= 1/
R
2
+ 1/
R
3
+ 1/
R
4
gives an equivalent resistance of
234
23
24
34
(50.0 )(50.0 )(75.0 )
(50.0 )(50.0 ) (50.0 )(75.0 ) (50.0 )(75.0 )
18.8 .
RRR
R
RR RR RR
Ω
ΩΩ
==
++
Ω
Ω
+Ω
Ω
Ω
=Ω
Thus, considering the series contribution of resistor
R
1
, the equivalent resistance for the
network is
R
eq
=
R
1
+
R
= 100
Ω
+ 18.8
Ω
= 118.8
Ω ≈
119
Ω
.
(b)
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Resistance

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