40. (a) Resistors R2, R3and R4are in parallel. By finding a common denominator and simplifying, the equation 1/R= 1/R2+ 1/R3+ 1/R4gives an equivalent resistance of 234232434(50.0 )(50.0 )(75.0 )(50.0 )(50.0 ) (50.0 )(75.0 ) (50.0 )(75.0 )18.8 .RRRRRR RR RRΩΩΩ==++ΩΩ+ΩΩΩ=ΩThus, considering the series contribution of resistor R1, the equivalent resistance for the network is Req= R1+ R= 100 Ω+ 18.8 Ω= 118.8 Ω ≈119 Ω. (b)
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.