ch27-p044 - R 1 and R 2 and avoids R 3 altogether. Since...

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44. (a) When R 3 = 0 all the current passes through R 1 and R 3 and avoids R 2 altogether. Since that value of the current (through the battery) is 0.006 A (see Fig. 27-54(b)) for R 3 = 0 then (using Ohm’s law) R 1 = (12 V)/(0.006 A) = 2.0 × 10 3 . (b) When R 3 = all the current passes through
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Unformatted text preview: R 1 and R 2 and avoids R 3 altogether. Since that value of the current (through the battery) is 0.002 A (stated in problem) for R 3 = then (using Ohms law) R 2 = (12 V)/(0.002 A) R 1 = 4.0 10 3 ....
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