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If there were
n
+1 parallel resistors, then
battery
battery
1
eq
1
2
n
VV
n
i
R
nR
+
+
==
+
.
For the relative increase to be 0.0125 ( =
1/80 ), we require
i
n+
1
–
i
n
i
n
=
i
n+
1
i
n
– 1 =
(1
)
/
(2
)
1
/(
1)
nn
+
+
−
+
=
1
80
.
This leads to the seconddegree equation
n
2
+ 2
n
– 80
= (
n
+ 10)(
n
–
8) = 0.
Clearly the only physically interesting solution to this is
n
= 8. Thus, there are eight
resistors in parallel (as well as that resistor in series shown towards the bottom) in Fig.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Current, Resistance

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