baaCA222323283281530 380 100 250 10169 100 250 102 75 10310 10−+=×−××⋅+×=×⋅−−−−chchchchch chρρ...mmmmΩΩΩThus, iC=××⋅=−0 250 102 75 102 0011132815...AmA3chchbgΩΩ. (b) Similarly, ()()3381530.380 10 m0.250 10 m1.69 10m2.00A0.893A.3.10 10mAi−−⎡⎤×−××Ω⋅⎢⎥⎣⎦==×Ω⋅(c) Consider the copper wire. If Vis the potential difference, then the current is given by V = iCRC= iCρCL/πa2, so LaViCC×=−−ππ23280 250 1012 0111169 10126bgbgbgchmVAmm.Ω47. (a) The copper wire and the aluminum sheath are connected in parallel, so the potential difference is the same for them. Since the potential difference is the product of the current and the resistance, iCRC= iARA, where iCis the current in the copper, iAis the current in the aluminum, RCis the resistance of the copper, and RAis the resistance of the aluminum. The resistance of either component is given by
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