Ch27-p050 - 50(a Since i =(r Rext and imax =/r we have Rext = R(imax/i 1 where r = 1.50 V/1.00 mA = 1.50 103 Thus Rext =(1.5 103(1 0.100 1 = 1.35

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50. (a) Since i = ε /( r + R ext ) and i max = / r , we have R ext = R ( i max / i – 1) where r = 1.50 V/1.00 mA = 1.50 × 10 3 . Thus, 34 ext (1.5 10 )(1/ 0.100 1) 1.35 10 R = × (b) 33 ext (1.5 10 )(1/ 0.500 1) 1.5 10 R
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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