eqeqeq0(12.0 V)(68.0 )'4.86 V.68.0 100VRViRRRεΩ====+Ω+Ω(a) The ammeter reading is '4.86 V0.0552 A.85.0 3.00AVi=+Ω(b) As shown above, the voltmeter reading is '4.86V.V=(c) R' = V’/i= 4.86 V/(5.52 ×10–2A) = 88.0 Ω. (d) Since 'AR=−, if RAis decreased, the difference between R’ and Rdecreases. In fact, when RA= 0, R’=R. 53. Since the current in the ammeter is i, the voltmeter reading is V’ =V+ i RA= i (R + RA), or R = V’/i – R
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.