62. (a) The potential difference Vacross the plates of a capacitor is related to the charge qon the positive plate by V = q/C, where Cis capacitance. Since the charge on a discharging capacitor is given by q = q0 e–t/τ, this means V = V0e–t/where V0is the initial potential difference. We solve for the time constant
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.