()( )2362221.0s2.00221.0 10 C1.0 101.0W,1.0stttqRPeeeτ−−−−××Ω===where tis again measured in seconds. 64. (a) The initial energy stored in a capacitor is given by 20/2 ,CUqC=where Cis the capacitance and q0is the initial charge on one plate. Thus qCUC06310100501010×=×...FJC.chbg(b) The charge as a function of time is given byqqet=−0, where is the capacitive time constant. The current is the derivative of the charge idqdtqet=−=−0, and the initial current is i0= q0/. The time constant is RC( )( )661.0 10 F 1.0 10−Ω=. Thus i03310 1010=×=×.CsAchbg. (c) We substitute 0te−=into VC= q/Cto obtain 31.0 s31.0061.0 10 C1.0 10 V
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