ch27-p065

# ch27-p065 - 65. At t = 0 the capacitor is completely...

This preview shows pages 1–2. Sign up to view the full content.

65. At t = 0 the capacitor is completely uncharged and the current in the capacitor branch is as it would be if the capacitor were replaced by a wire. Let i 1 be the current in R 1 and take it to be positive if it is to the right. Let i 2 be the current in R 2 and take it to be positive if it is downward. Let i 3 be the current in R 3 and take it to be positive if it is downward. The junction rule produces iii 123 = + , the loop rule applied to the left-hand loop produces ε = iR iR 11 2 2 0, and the loop rule applied to the right-hand loop produces 22 33 0 = . Since the resistances are all the same we can simplify the mathematics by replacing R 1 , R 2 , and R 3 with R . (a) Solving the three simultaneous equations, we find i R 1 3 6 3 2 3 212 10 3 0 73 10 11 10 == × × . . . V A ch c h , (b) () 3 4 2 6 1.2 10 V 5.5 10 A, 3 30 .7310 i R × = × ×Ω and (c) 4 32 5.5 10 A. ii == × At t = the capacitor is fully charged and the current in the capacitor branch is 0. Thus, i 1 = i 2 , and the loop rule yields = 12 0.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

### Page1 / 2

ch27-p065 - 65. At t = 0 the capacitor is completely...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online