69. (a) The charge on the positive plate of the capacitor is given by qCet=−−ετ1ch, where is the emf of the battery, Cis the capacitance, and is the time constant. The value of is = RC= (3.00 ×106Ω)(1.00 ×10–6F) = 3.00 s. At t= 1.00 s, t/= (1.00 s)/(3.00 s) = 0.333 and the rate at which the charge is increasing is ()( )60.33371.00 10F 4.00V9.55 10 C s.3.00stdqCeedt−−−−×===×(b) The energy stored in the capacitor is given by 2,2CqUC=and its rate of change is dUdtqCdqdtC=. Now eet=−=×−=×− −1100 104 001113 1060 3336chchbgch....VC,so 67661.13 10 C9.55 10 C s1.08 10 W.1.00 10 FCdUqdqdtC dt−−⎛⎞××=×⎜⎟×⎝⎠(c) The rate at which energy is being dissipated in the resistor is given by
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.