71. (a) In the process described in the problem, no charge is gained or lost. Thus, q= constant. Hence, ()31112 22121502003.0 10 V.10CqCV CVV VC⎛⎞==⇒===×⎜⎟⎝⎠(b) Eq. 27-39, with τ= RC, describes not only the discharging of qbut also of V. Thus, ()912003000ln300 1010 10F ln100tVVVetRCV−−=⇒==×Ω×which yields t= 10 s. This is a longer time than most people are inclined to wait before
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.