ch27-p082 - 82. (a) The four resistors R1, R2, R3 and R4 on...

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(e) By the loop rule (proceeding clockwise), 30V – i 4 (1.5 ) – i 5 (2.0 ) = 0 readily yields i 5 = 7.5 A. 82. (a) The four resistors R 1 , R 2 , R 3 and R 4 on the left reduce to 34 12 eq 12 34 7.0 3.0 10 RR RRR RR RR =+= + =Ω +Ω = ++ With 30 V ε = across R eq the current there is i 2 = 3.0 A. (b) The three resistors on the right reduce to
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