ch27-p083 - 83. (a) We analyze the lower left loop and find...

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83. (a) We analyze the lower left loop and find i 1 = ε 1 / R = (12.0 V)/(4.00 ) = 3.00 A. (b) The direction of i 1 is downward. (c) Letting R = 4.00 , we apply the loop rule to the tall rectangular loop in the center of the figure (proceeding clockwise): () 2 21 2 2 0 2 i iR R ⎛⎞ ++ +− = ⎜⎟ ⎝⎠ . Using the result from part (a), we find i 2 = 1.60 A. (d) The direction of i 2 is downward (as was assumed in writing the equation as we did). (e) Battery 1 is supplying this power since the current is in the "forward" direction
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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