89. When S is open for a long time, the charge on C is q i = ε 2 C . When S is closed for a long time, the current i in R 1 and R 2 is i = ( 2 – 1 )/( R 1 + R 2 ) = (3.0 V – 1.0 V)/(0.20 Ω + 0.40 Ω ) = 3.33 A. The voltage difference V across the capacitor is then V = 2 – iR
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.