ch27-p097 - → ∞ the current to the capacitor reduces to...

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97. (a) The capacitor is initially uncharged, which implies (by the loop rule) that there is zero voltage (at t = 0) across the R 2 = 10 k resistor, and that 30 V is across the R 1 =20 k resistor. Therefore, by Ohm;s law, i 10 = (30 V)/(20 k ) = 1.5 × 10 –3 A. (b) Similarly, i 20 = 0. (c) As t
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Unformatted text preview: → ∞ the current to the capacitor reduces to zero and the 20 k Ω and 10 k Ω resistors behave more like a series pair (having the same current), equivalent to 30 k Ω . The current through them, then, at long times, is i = (30 V)/(30 k Ω ) = 1.0 × 10 –3 A....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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