ch27-p101 - are connected in series, i r = i R and total =...

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101. When all the batteries are connected in parallel, each supplies a current i ; thus, i R = Ni . Then from ε = ir + i R R = ir + Nir , we get i R = N /[( N + 1) r ]. When all the batteries
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Unformatted text preview: are connected in series, i r = i R and total = N = Ni r r + i R R = Ni R r + i R r , so i R = N /[( N + 1) r ]....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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