(c) The loop rule (counterclockwise around the left loop) gives ()( ) ( )111220iRε++++−=where i2has been assumed leftward. This yields i3= 0.180 A. (d) A positive value of i3implies that our assumption on the direction is correct, i.e., it flows leftward. (e) The junction rule tells us that the current through the 12 V battery is 0.180 + 0.0600 =
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