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106. (a)
R
2
and
R
3
are in parallel; their equivalence is in series with
R
1
. Therefore,
23
eq
1
300
.
RR
=
+=
Ω
+
(b) The current through the battery is
ε
/
R
eq
= 0.0200 A, which is also the current through
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 Spring '08
 Any
 Physics, Current

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