ch27-p110 - 110. The power delivered by the motor is P =...

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(a) The larger i is 3.41 A. (b) We use V = ε – ir = 2.00 V – i (0.500 ). We substitute value of i obtained in part (a) into the above formula to get V = 0.293 V. (c) The smaller i is 0.586 A. (d) The corresponding V is 1.71 V. 110. The power delivered by the motor is P = (2.00 V)(0.500 m/s) = 1.00 W. From P = i 2 R motor
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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