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−
±
k
direction (since
±±
±
ik
j
×− =
e
j
). Note that the charge is positive; also note that we need
to assume
B
y
= 0. The magnitude 
B
z
 is given by Eq. 283 (with
φ
= 90°). Therefore, with
2
1.0 10
kg
m
−
=×
,
4
2.0 10 m/s
v
and
5
8.0 10 C
q
−
, we find
ˆˆ
ˆ
k
k
( 0.061 T)k
z
mg
BB
qv
⎛⎞
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Charge, Force, Gravity

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