ch28-p017 - 17. (a) From K = 1 me v 2 we get 2 c hc h . . 2...

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17. (a) From Km v e = 1 2 2 we get v K m e == ×× × 2 2 120 10 160 10 911 10 205 10 31 9 31 7 .. . eV eV J kg ms c hc h (b) From / e rm vq B = we get B mv qr e −− 2 05 10 160 10 250 10 467 10 31 7 19 2 4 . kg m s Cm T. ch c h (c) The “orbital” frequency is f v r × ×
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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