Its average energy during the accelerating process is 8.3 MeV. The radius of the orbit is given by r = mv/qB, where vis the deuteron’s speed. Since this is given by vKm=2, the radius is rmqBKmqBKm==212.For the average energy r=××××=−−−2 8 3 10160 10334 10160 101570 3756192719....eVJ eVkgCTm.chchchchbgThe total distance traveled is about n2πr= (104)(2π)(0.375) = 2.4 ×102m. 35. We approximate the total distance by the number of revolutions times the circumference of the orbit corresponding to the average energy. This should be a good
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.