ch28-p035 - 35. We approximate the total distance by the...

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Its average energy during the accelerating process is 8.3 MeV. The radius of the orbit is given by r = mv / qB , where v is the deuteron’s speed. Since this is given by vK m = 2 , the radius is r m qB K mq B Km == 21 2. For the average energy r = ×× × × = −− 2 8 3 10 160 10 334 10 160 10 157 0 375 61 9 2 7 19 .. . . eV J eV kg CT m. ch c h c h c hb g The total distance traveled is about n 2 π r = (104)(2 π )(0.375) = 2.4 × 10 2 m. 35. We approximate the total distance by the number of revolutions times the circumference of the orbit corresponding to the average energy. This should be a good
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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