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Its average energy during the accelerating process is 8.3 MeV. The radius of the orbit is
given by
r = mv
/
qB
, where
v
is the deuteron’s speed. Since this is given by
vK
m
=
2
,
the radius is
r
m
qB
K
mq
B
Km
==
21
2.
For the average energy
r
=
××
×
×
=
−−
−
2 8 3 10
160 10
334 10
160 10
157
0 375
61
9
2
7
19
..
.
.
eV
J eV
kg
CT
m.
ch
c
h
c
h
c
hb
g
The total distance traveled is about
n
2
π
r
= (104)(2
π
)(0.375) = 2.4
×
10
2
m.
35. We approximate the total distance by the number of revolutions times the
circumference of the orbit corresponding to the average energy. This should be a good
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy

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