ch28-p040 - ˆ ( 16j) N − . (b) The force exerted on the...

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40. (a) From symmetry, we conclude that any x -component of force will vanish (evaluated over the entirety of the bent wire as shown). By the right-hand rule, a field in the ± k direction produces on each part of the bent wire a y -component of force pointing in the ± j direction; each of these components has magnitude | | | | sin30 (2.0 A)(2.0 m)(4.0 T)sin30 8N. y Fi B = ° = G A Therefore, the force on the wire shown in the figure is ˆ (1
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Unformatted text preview: ˆ ( 16j) N − . (b) The force exerted on the left half of the bent wire points in the − ± k direction, by the right-hand rule, and the force exerted on the right half of the wire points in the + ± k direction. It is clear that the magnitude of each force is equal, so that the force (evaluated over the entirety of the bent wire as shown) must necessarily vanish....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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