Ch28-p044 - 44(a The magnetic force on the wire is FB = idB pointing to the left Thus v = at = FB t idBt(9.13103 A(2.56 102 m(5.63102 T(0.0611s = =

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44. (a) The magnetic force on the wire is F B = idB , pointing to the left. Thus 322 5 2 (9.13 10 A)(2.56 10 m)(5.63 10 T)(0.0611s) 2.41 10 kg 3.34 10 m/s.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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