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47. The applied field has two components:
B
x
>
0 and
B
z
>
0. Considering each straight
segment of the rectangular coil, we note that Eq. 2826 produces a nonzero force only
for the component of
G
B
which is perpendicular to that segment; we also note that the
equation is effectively multiplied by
N
= 20 due to the fact that this is a 20turn coil.
Since we wish to compute the torque about the hinge line, we can ignore the force acting
on the straightsegment of the coil which lies along the
y
axis (forces acting at the axis of
rotation produce no torque about that axis). The top and bottom straightsegments
experience forces due to Eq. 2826 (caused by the
B
z
component), but these forces are (by
the righthand rule) in the ±
y
directions and are thus unable to produce a torque about the
y
axis. Consequently, the torque derives completely from the force exerted on the
straightsegment located at
x
= 0.050 m, which has length
L
= 0.10 m and is shown in
Figure 2847 carrying current in the –
y
direction. Now, the
B
z
component will produce a
force on this straightsegment which points in the –
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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