Ch28-p047 - 47 The applied field has two components Bx > 0 and Bz > 0 Considering each straightsegment of the rectangular coil we note that Eq

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47. The applied field has two components: B x > 0 and B z > 0. Considering each straight- segment of the rectangular coil, we note that Eq. 28-26 produces a non-zero force only for the component of G B which is perpendicular to that segment; we also note that the equation is effectively multiplied by N = 20 due to the fact that this is a 20-turn coil. Since we wish to compute the torque about the hinge line, we can ignore the force acting on the straight-segment of the coil which lies along the y axis (forces acting at the axis of rotation produce no torque about that axis). The top and bottom straight-segments experience forces due to Eq. 28-26 (caused by the B z component), but these forces are (by the right-hand rule) in the ± y directions and are thus unable to produce a torque about the y axis. Consequently, the torque derives completely from the force exerted on the straight-segment located at x = 0.050 m, which has length L = 0.10 m and is shown in Figure 28-47 carrying current in the – y direction. Now, the B z component will produce a force on this straight-segment which points in the –
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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