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33
7
sin
2
sin
2 (0.018 m)(4.6 10 A)(3.4 10 T)sin 20
6.0 10 N.
v
Fi
B
d
s a
i
B
θθ
π
−−
−
===
××
°
=×
∫
π
We note that
i, B
, and
θ
have the same value for every segment and so can be factored
from the integral.
49. Consider an infinitesimal segment of the loop, of length
ds
. The magnetic field is
perpendicular to the segment, so the magnetic force on it has magnitude
dF = iB ds
. The
horizontal component of the force has magnitude
(c
o
s)
h
dF
iB
ds
=
and points inward toward the center of the loop. The vertical component has magnitude
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

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