ch28-p050

# ch28-p050 - Thus, when it takes the shape of a square the...

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50. The insight central to this problem is that for a given length of wire (formed into a rectangle of various possible aspect ratios), the maximum possible area is enclosed when the ratio of height to width is 1 (that is, when it is a square). The maximum possible value for the width, the problem says, is x = 4 cm (this is when the height is very close to zero, so the total length of wire is effectively 8 cm).
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Unformatted text preview: Thus, when it takes the shape of a square the value of x must be of 8 cm; that is, x = 2 cm when it encloses maximum area (which leads to a maximum torque by Eq. 28-35 and Eq. 28-37) of A = (0.020 m) 2 = 0.00040 m 2 . Since N = 1 and the torque in this case is given as 4.8 10 4 N . m, then the aforementioned equations lead immediately to i = 0.0030 A....
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