51. (a) The current in the galvanometer should be 1.62 mA when the potential difference across the resistor-galvanometer combination is 1.00 V. The potential difference across the galvanometer alone is iRg=×=−162 1075301223...AV,chbgΩso the resistor must be in series with the galvanometer and the potential difference across it must be 1.00 V – 0.122 V = 0.878V. The resistance should be R=−0878162 105423.VAchΩ(b) As stated above, the resistor is in series with the galvanometer. (c) The current in the galvanometer should be 1.62 mA when the total current in the
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