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53. We use Eq. 2837 where
G
µ
is the magnetic dipole moment of the wire loop and
G
B
is
the magnetic field, as well as Newton’s second law. Since the plane of the loop is parallel
to the incline the dipole moment is normal to the incline. The forces acting on the
cylinder are the force of gravity
mg
, acting downward from the center of mass, the
normal force of the incline
F
N
, acting perpendicularly to the incline through the center of
mass, and the force of friction
f
, acting up the incline at the point of contact. We take the
x
axis to be positive down the incline. Then the
x
component of Newton’s second law for
the center of mass yields
mg
f
ma
sin
.
θ
−
=
For purposes of calculating the torque, we take the axis of the cylinder to be the axis of
rotation. The magnetic field produces a torque with magnitude
B
sin
, and the force of
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 Spring '08
 Any
 Physics, Force

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