60. Eq. 28-39 gives U= −µ→·B→= −µB cos φ, so at = 0 (corresponding to the lowest point on the graph in Fig. 28-52) the mechanical energy is K + U= Ko+ (−µB) = 6.7×10−4 J + (−5×10−4 J) = 1.7×10−4 J. The turning point occurs where K= 0, which implies
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.