ch28-p064 - 64. Looking at the point in the graph (Fig....

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64. Looking at the point in the graph (Fig. 28-54(b)) corresponding to i 2 = 0 (which means that coil 2 has no magnetic moment) we are led to conclude that the magnetic moment of coil 1 must be 52 1 2.0 10 A m . µ Looking at the point where the line crosses the axis (at i 2 = 5.0 mA) we conclude (since the magnetic moments cancel there) that the magnitude of coil 2’s moment must also be 2 2.0 10 A m = ×⋅ when 2 0.0050 A i = which means (Eq. 28-35)
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