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Unformatted text preview: 68. (a) The largest value of force occurs if the velocity vector is perpendicular to the field.
Using Eq. 283,
FB,max = q vB sin (90°) = ev B = (1.60 × 10– 19 C) (7.20 × 106 m/s) (83.0 × 10– 3 T)
= 9.56 × 10– 14 N.
(b) The smallest value occurs if they are parallel: FB,min = q vB sin (0) = 0.
(c) By Newton’s second law, a = FB/me = q vB sin θ /me, so the angle θ between v and
B is θ = sin −1 F m a I = sin
GH q vB JK
e LM c9.11 × 10 kghd4.90 × 10 m s i
.
MN c160 × 10 Chc7.20 × 10 m shc83.0 × 10
−31 −1 −16 14 6 2 −3 OP
= 0.267° .
Th P
Q ...
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 Spring '08
 Any
 Physics, Force

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