This preview shows page 1. Sign up to view the full content.
69. (a) We use G G G τµ =× B , where G µ points into the wall (since the current goes clockwise around the clock). Since G B points towards the one-hour (or “5-minute’’) mark, and (by the properties of vector cross products) G τ must be perpendicular to it, then (using the
This is the end of the preview. Sign up to access the rest of the document.